from itertools import *

# value of a card represented as a number from 0 to 12
def value(card):
    return card % 13

ACE = 12

# value of a card represented as a number 0, 1, 2, or 3
def suit(card):
    return card / 13

SPADE = 3
HEART = 2
DIAMOND = 1
CLUB = 0

# count the number of poker hands of a given kind
def num_hands(kind):
    num = 0
    for hand in combinations(range(52), 5):
        if kind(hand):
            num = num + 1
    return num
    
def four_of_a_kind(hand):
    v = map(value, hand)      
    return (v[0] == v[1] == v[2] == v[3]) or (v[0] == v[1] == v[2] == v[4]) or (v[0] == v[1] == v[3] == v[4]) or (v[0] == v[2] == v[3] == v[4]) or (v[1] == v[2] == v[3] == v[4])

def straight_flush(hand):
    s = map(suit, hand)
    return s[0] == s[1] == s[2] == s[3] == s[4]

def all_four_suits(hand):
    num_cards = [0] * 4    # number of cards of each suit
    for i in range(5):
        num_cards[suit(hand[i])] += 1
    return num_cards[SPADE] > 0 and num_cards[HEART] > 0 and num_cards[DIAMOND] > 0 and num_cards[CLUB] > 0 

def at_least_one_ace(hand):
    aces = map(lambda card: value(card) == ACE, hand)
    return aces[0] or aces[1] or aces[2] or aces[3] or aces[4]